AB=CD,BE=DF,AF=CE求证BE‖DF

AB=CD,BE=DF,AF=CE求证BE‖DF AB=CD,DF垂直AC,BE垂直AC,DF=BE.求证:AF=CE AB=CD,AF=CE,BE⊥AC,DF⊥AC,求证BE=DF 在四边形ABCD中,AB=CD,BE=DF,AF⊥AB,CE⊥CD,求证AB∥CD 已知AB=CD,BE=DF,AF=CE 求证：△ABE≌△CDF 已知ab平行cd,ab=CD,BE=DF,求证af平行ce,ae=cf 已知AB=CD,AF=CE,BE⊥AC于E,DF⊥AC于F.求证：AB//CD AB=CD,DF垂直CD于点F,BE垂直AC于点E,DF=BE,求证AF=CE 已知∠1=∠2,CB=CD,CE⊥AB,CF⊥AF,求证 BE=DF AB∥CD,AB=CD,AF=CE,那么BE与DF平行吗?为什么 已知四边形ABCD,延长AB到E使BE=DF,连接CE、AF.求证:AF=CE平行四边形 延长CD到F 如图,在四边形ABCD中,AB=CD,BE=DF,AF⊥AB,CE⊥CD,求证:AB||CD 如图,AB=CD,DF垂直AC于F ,BE垂直AC于E,DF=BE,求证AF=CE. 如图AB=CD AF平行DF CF平行BE 求证AF=DE 如图AB=CD AF∥DF CF∥BE 求证AF=DE 如图,BE=DF,∠BEC=AFD,AF=CE,求证（1）AB=CD （2）AB∥CD 在四边形ABCD中,AB‖CD,AB⊥CD,∠AEB=∠CED.F为BC的中点,求证AF=DF=0.5（BE+CE) 如图,ab=cd,ae=df,ce=fb,求证af=de