lim(x→0) (1-cos(1-cosx))/(arctanx^2)^2求极限
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/16 13:45:12
xRmkP+0h͛D~ID&6}EtcZ&Jl"7٧T
zH0ϯUGWkƢ TYP%bY()زDh6H / 5Q,,9DQ"TFZZ?- `UdSᱦ阢ySn%; Ҩ}7ӳam >ݣdF'[l{}!~f>@ TZaʊ! } _(
lim(x→0)(1/x)*cos(1/x)
求极限lim(x→0) cos(1/x)
求lim(x→0)x cos 1/x lim(x→∞)x^2/ (3x-1)的极限
lim x趋向0 (1+cos^2(1/x))^x
求函数极限:lim(x->0) (cos x)^(1/x)
lim((cos( √x))^(1/x)) x……0+
求函数极限lim x→0 e^x-x-1/x cos x
lim x->0 cos(2x)-1 / cosx -1 =
lim[cos(1/x)]^2,x--->0,极限为什么不存在
求极限:lim(x→0)ln(1+x²)/ (sec x- cos x)
lim(x→0) [1-cos(x^2)]/sin(x^2)tan(x^2)]=?
lim(cos(sqrt(x)))^1/x
lim(x→0)根号(1+x^3)-1/1-cos根号(x-sinx)
lim(x→0)根号(1+x^3)-1/1-cos根号(x-sinx) ..
求极限lim(x→0)(1-根号cosx)/[x(1-cos根号x)]
lim(x→0)(1-根号cosx)/(x(1-cos根号x))
求lim(x→0+) ( 2/π*cosπ/2(1-x))/x的极限
求lim(x→0) (1-cos x) /x^2的极限