已知01,则下列不等式中成立的是（ ）A.log(b)(1/b)＜log(a)(b)＜log(a)(1/b)B.log(a)(b)＜log(b)(1/b)＜log(a)(1/b)C.log(a)(b)＜log(a)(1/b)＜log(b)(1/b)D.log(b)(1/b)＜log(a)(1/b)＜log(a)(b)

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