若x1满足2x+2的x方=5,x2满足2x+2log2(x-1)=5,求x1+x2
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若x1满足2x+2的x方=5,x2满足2x+2log2(x-1)=5,求x1+x2
若x1满足2x+2的x方=5,x2满足2x+2log2(x-1)=5,求x1+x2
若x1满足2x+2的x方=5,x2满足2x+2log2(x-1)=5,求x1+x2
化简到 2^(x1-1)=1.5-(x1-1) log2(x2-1)=1.5-(x2-1)
反函数所以2^x中的x的值和y=log2(x)中的y值是相等的
所以x2-1=1.5-(x1-1)
x1-1=1.5(x2-1)
同时成立x1-1+x2-1=1.5
故3.5
bzd
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