计算(2m)^2+(2-m)^2=2
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计算(2m)^2+(2-m)^2=2
计算(2m)^2+(2-m)^2=2
计算(2m)^2+(2-m)^2=2
(2m)²+(2-m)²=2
4m²+4-4m+m²=2
5m²-4m+2=0
Δ=b²-4ac=(-4)²-4×5×2=16-40=-24<0
所以该方程无实数根.
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