作业帮化简(sin²α/1-cosα)-cosα
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化简(sin²α/1-cosα)-cosα
化简(sin²α/1-cosα)-cosα
化简(sin²α/1-cosα)-cosα
[sin²α/(1-cosα)]-cosα
=[(1-cos²α)/(1-cosα)]-cosα
=(1+cosα)(1-cosα)/(1-cosα) -cosα
=1+cosα-cosα
=1
sin²a/(1-cosa)-cosa
=(1-cos²a)/(1-cosa)-cosa
=[(1+cosa)(1-cosa)]/(1-cosa)-cosa
=(1+cosa)-cosa
=1+cosa-cosa
=1