lim x趋于无穷,xsin(2x/1+x^2)=

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/02 22:31:57
lim x趋于无穷,xsin(2x/1+x^2)=
xjA_eX0EPΎfẘ A=F<#c؛u Bv]]ïe{xL_?,>]~~PLd^mI8 'uՠy?L NC5c~4nl>Fz: {>ngx]9ien:/.x <9""Dq٢Ȉ҉yeO=jJKvY AYpdt Y zG4.n*oWlf+8f P>OK\/7hzK0m#_2Qɒu-N*_NvynFny5=q(eAԈXkOL8r>@h#XDQ P+!= e D8cZsLE

lim x趋于无穷,xsin(2x/1+x^2)=
lim x趋于无穷,xsin(2x/1+x^2)=

lim x趋于无穷,xsin(2x/1+x^2)=
解:
lim(x→无穷)xsin(2x/(1+x^2))
=lim(x→无穷)xsin[(2/x)/(1/x^2 +1)]
=lim(1/x→0)x[(2/x)/(1/x^2 +1)]
=lim(1/x→0)[2/(1/x^2 +1)]
=2/1=2

啊啊啊 答案是2