若x/(x^2-x+1)=4,求分式x^2/(x^4+x^2+1)的值

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 12:37:05
若x/(x^2-x+1)=4,求分式x^2/(x^4+x^2+1)的值
x){ѽB_"HBPDƦmO@&@P {lI֣_`gCM: nysf=t9KȘkQD` r0\#S}C345w.6hе@EHu`5ng0vT>sXyLRF 1Vv

若x/(x^2-x+1)=4,求分式x^2/(x^4+x^2+1)的值
若x/(x^2-x+1)=4,求分式x^2/(x^4+x^2+1)的值

若x/(x^2-x+1)=4,求分式x^2/(x^4+x^2+1)的值
∵x/(x^2-x+1)=4
∴﹙x²-x+1﹚/x=1/4
x+1/x=5/4
x²+2+1/x²=25/16
x²+1/x²=﹣7/16
∵﹙ x^4+x²+1﹚/x²=x²+1/x²+1=﹣7/16+1=9/16
∴ x²/﹙x^4+x²+1﹚=16/9.