若x/(x^2-x+1)=4,求分式x^2/(x^4+x^2+1)的值
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若x/(x^2-x+1)=4,求分式x^2/(x^4+x^2+1)的值
若x/(x^2-x+1)=4,求分式x^2/(x^4+x^2+1)的值
若x/(x^2-x+1)=4,求分式x^2/(x^4+x^2+1)的值
∵x/(x^2-x+1)=4
∴﹙x²-x+1﹚/x=1/4
x+1/x=5/4
x²+2+1/x²=25/16
x²+1/x²=﹣7/16
∵﹙ x^4+x²+1﹚/x²=x²+1/x²+1=﹣7/16+1=9/16
∴ x²/﹙x^4+x²+1﹚=16/9.
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