因式分解 速回xy﹙xy+1﹚+﹙xy+3﹚-2﹙x+y+1/2﹚-﹙x+y-1﹚²
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 06:10:45
xQJ@~Aa;=(E$eW[
g\ĂH=A}-G#b=aj$+NYu(%ZPZS=-m#lwKi,oU-|Yx^w"D(vkt i7ipw9
因式分解 速回xy﹙xy+1﹚+﹙xy+3﹚-2﹙x+y+1/2﹚-﹙x+y-1﹚²
因式分解 速回
xy﹙xy+1﹚+﹙xy+3﹚-2﹙x+y+1/2﹚-﹙x+y-1﹚²
因式分解 速回xy﹙xy+1﹚+﹙xy+3﹚-2﹙x+y+1/2﹚-﹙x+y-1﹚²
原式=x^2y^2+2xy-2x-2y+2-(x+y-1)^2
=x^2y^2+2xy-2(x+y-1)-(x+y-1)^2
=x^2y^2+2xy-[2(x+y-1)+(x+y-1)^2]
=x^2y^2+2xy-(x+y-1)(x+y+1)
=x^2y^2+2xy-(x+y)^2+1
=x^2y^2+2xy-(x^2+2xy+y^2)+1
=x^2y^2-x^2-y^2+1
=x^2(y^2-1)-(y^2-1)
=(x^2-1)(y^2-1)
=(x+1)(x-1)(y+1)(y-1)
自己做吧
xxyy+xy+xy+3-2x-2y-1-xx-yy-2xy-1+2x+2y
=xxyy-xx-yy+1