已知sin(x+y)=1,求证:tan(2x+y)+tany=0请哪位能帮我尽快解决,我真的很着急要用
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已知sin(x+y)=1,求证:tan(2x+y)+tany=0请哪位能帮我尽快解决,我真的很着急要用
已知sin(x+y)=1,求证:tan(2x+y)+tany=0
请哪位能帮我尽快解决,我真的很着急要用
已知sin(x+y)=1,求证:tan(2x+y)+tany=0请哪位能帮我尽快解决,我真的很着急要用
由sin(x+y)=1 可知x+y=90度
tan(2x+y)+tany
tan(2x+y+y)
tan(2x+2y)
tan180度
因为:tan180度=0(常识!)
所以:tan(2x+y)+tany=0
x+y=90
tan(2x+y)=tan(90+x)=-cotx
tany=tan(90-x)=cotx
tan(2x+y)+tany=-cotx+cotx=0
不用很复杂的。
左式得x和y互余,
tan(2x+y)+tany=tan(x+π/2)+cotx=-cotx+cotx=0
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