设函数y=f(x)=sin x ^2+(2a-1)sinx+a ^2+1/4,已知xЕ[5π/6,3π/2],1/3设函数y=f(x)=sin ^2x +(2a-1)sinx+a ^2+1/4，已知xЕ[5π/6,3π/2],1/3

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设函数y=f(x)=sin x ^2+(2a-1)sinx+a ^2+1/4,已知xЕ[5π/6,3π/2],1/3设函数y=f(x)=sin ^2x +(2a-1)sinx+a ^2+1/4，已知xЕ[5π/6,3π/2],1/3
x){nϦnMӨд-SP30J5r+A|C}7=h f:@(VP1qF ،yA6IErNs~ J{: zt LK=bYiϦKJ&V<ݜhkd W؂ 6}X']F`ӽaAjF>7ٜ64Zyv@-

设函数y=f(x)=sin x ^2+(2a-1)sinx+a ^2+1/4,已知xЕ[5π/6,3π/2],1/3设函数y=f(x)=sin ^2x +(2a-1)sinx+a ^2+1/4，已知xЕ[5π/6,3π/2],1/3
设函数y=f(x)=sin x ^2+(2a-1)sinx+a ^2+1/4,已知xЕ[5π/6,3π/2],1/3
设函数y=f(x)=sin ^2x +(2a-1)sinx+a ^2+1/4，已知xЕ[5π/6,3π/2],1/3

设函数y=f(x)=sin x ^2+(2a-1)sinx+a ^2+1/4,已知xЕ[5π/6,3π/2],1/3设函数y=f(x)=sin ^2x +(2a-1)sinx+a ^2+1/4，已知xЕ[5π/6,3π/2],1/3
y=（sinx+a-1/2）^2+a
故要取放f（x）max,即a=1,sinx=1/2,即x=5π/6时
f(x)=2
当a=1/3,sinx=1/6时取得最小值放f（X）=1/3

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