求不定积分f[(e^3x+e^x)/(e^4x-e^2x+1)]dx

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求不定积分f[(e^3x+e^x)/(e^4x-e^2x+1)]dx
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求不定积分f[(e^3x+e^x)/(e^4x-e^2x+1)]dx
求不定积分f[(e^3x+e^x)/(e^4x-e^2x+1)]dx

求不定积分f[(e^3x+e^x)/(e^4x-e^2x+1)]dx
令 e^x=u ,则 dx = du/u
原式 = ∫ (u³+u)/(u(u^4-u²+1)) du
=∫ (u²+1)/(u^4-u²+1) du
=∫ (1+1/u²)/(u²-1+1/u²) du
=∫ d(u-1/u)/((u-1/u)²+1)
=arc tan (u - 1/u)