若n是奇数,则{(1+i)/√2}^4n+{(1-i)/√2}^4n=多少题目有点麻烦 还望高手指教

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若n是奇数,则{(1+i)/√2}^4n+{(1-i)/√2}^4n=多少题目有点麻烦 还望高手指教
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若n是奇数,则{(1+i)/√2}^4n+{(1-i)/√2}^4n=多少题目有点麻烦 还望高手指教
若n是奇数,则{(1+i)/√2}^4n+{(1-i)/√2}^4n=多少
题目有点麻烦 还望高手指教

若n是奇数,则{(1+i)/√2}^4n+{(1-i)/√2}^4n=多少题目有点麻烦 还望高手指教

因为过程不好描述,我用公式做的过程,用图片发给你

(1+i)/√2=e^(iπ/4);(1-i)/√2=e^(-iπ/4)
{(1+i)/√2}^4n+{(1-i)/√2}^4n
=e^(inπ)+e^(-inπ)
=2cosnπ
=-2

拆开算,(1+i)2=2i ,(1+i )^4=-4,同理,(1-i)^4=-4,化简得(-2)^n …

2,很多年没接触数学啦!