|x+2|+|x-1|=9-|y+1|-|y-5|求x+y的最大值与最小值.
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|x+2|+|x-1|=9-|y+1|-|y-5|求x+y的最大值与最小值.
|x+2|+|x-1|=9-|y+1|-|y-5|求x+y的最大值与最小值.
|x+2|+|x-1|=9-|y+1|-|y-5|求x+y的最大值与最小值.
=Ix+2I+Ix-1I+Iy-5I+Iy+1I
≥Ix+2+x-1I+Iy-5+y+1I
=I2x+1I+I2y-4I
≥I2x+2y-3I
所以-9≤2x+2y-3≤9
-3≤x+y≤6
所以x+y的最大值为6,最小值为-3
先化简再求值 x(9x-y)-y(y-x)+(x-y)的平方,其中x=-1,y=2
9y=3x-(x-1),4(x+y)-(2x+4)=8y
已知x+y=a,2x-y=-2a,求[(x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
(x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3.
2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2
1-x+y-2x+9y=
(x-y)/4+(x+y)/5=1/4 (x+y)/9-(x-y)/3=//2(x-y)/4+(x+y)/5=1/4(x+y)/9-(x-y)/3=//2
解方程组 3(x+y)-2(x-y)=9,5(x+y)+2(x-y)=-1
解方程组:{3(x+y)-2(x-y)=9,5(x+y)+2(x-y)=-1}
解二元一次方程 {3(x+y)-4(x-y)=-9 x+y/2+x-y/6=1
已知4x=9y求(1)x+y/y (2)y-x/2x有关比例的
设x,y满足约束条件x+y>=1,x-y>=-1,2x-y
设x,y满足约束条件x+y>=1,x-y>=-1,2x-y
x+2y=2x+y+1=7x-y 求:2x-y?
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二元一次方程 :2(x+y)-(x-y)=3 (x+y)-2(x-y)=1
(3x-y)^2+(3x+y)(3x-y),x=1,y=-2