作业帮a²+b²-1/2a²-1/2[a+b]×b=1/2a²+1/2b²-1/2ab化简
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/15 05:58:02
![a²+b²-1/2a²-1/2[a+b]×b=1/2a²+1/2b²-1/2ab化简](/uploads/image/z/13307944-40-4.jpg?t=a%26%23178%3B%2Bb%26%23178%3B-1%2F2a%26%23178%3B-1%2F2%5Ba%2Bb%5D%C3%97b%3D1%2F2a%26%23178%3B%2B1%2F2b%26%23178%3B-1%2F2ab%E5%8C%96%E7%AE%80)
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a²+b²-1/2a²-1/2[a+b]×b=1/2a²+1/2b²-1/2ab化简
a²+b²-1/2a²-1/2[a+b]×b=1/2a²+1/2b²-1/2ab化简
a²+b²-1/2a²-1/2[a+b]×b=1/2a²+1/2b²-1/2ab化简
这是个恒等式啊,是要证明吧.
a²+b²-(1/2)a²-(1/2)(a+b)b
=a²+b²- a²/2-ab/2 -b²/2
=(1/2)a²/2+(1/2)b²-(1/2)ab
等式成立.
a²+b²-(1/2)a²-(1/2)(a+b)b
=a²+b²- a²/2-ab/2 -b²/2
=(1/2)a²+(1/2)b²-(1/2)ab