f(x+1)=x^2+2x+2,求f(x)的解析式设y=x+1x=y-1f(x+1)=x^2+2x+2f(y)=(y-1)^2+2(y-1)+2f(y)=y^2-2y+1+2y-2+2f(y)=y^2+1f(x)=x^2+1 f(y)=y^2-2y+1+2y-2+2怎样的来?

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 20:31:48
f(x+1)=x^2+2x+2,求f(x)的解析式设y=x+1x=y-1f(x+1)=x^2+2x+2f(y)=(y-1)^2+2(y-1)+2f(y)=y^2-2y+1+2y-2+2f(y)=y^2+1f(x)=x^2+1   f(y)=y^2-2y+1+2y-2+2怎样的来?
x)KӨ6Դ366y (|Vˋ募͛tOu*m*l+u ԧiTjj5A`P{:m+t* *ub S f*((Rق@<&HǂՃ]M'T !28\dR_`g3BWXa #h$ف 9

f(x+1)=x^2+2x+2,求f(x)的解析式设y=x+1x=y-1f(x+1)=x^2+2x+2f(y)=(y-1)^2+2(y-1)+2f(y)=y^2-2y+1+2y-2+2f(y)=y^2+1f(x)=x^2+1 f(y)=y^2-2y+1+2y-2+2怎样的来?
f(x+1)=x^2+2x+2,求f(x)的解析式设y=x+1
x=y-1
f(x+1)=x^2+2x+2
f(y)=(y-1)^2+2(y-1)+2
f(y)=y^2-2y+1+2y-2+2
f(y)=y^2+1
f(x)=x^2+1 f(y)=y^2-2y+1+2y-2+2怎样的来?

f(x+1)=x^2+2x+2,求f(x)的解析式设y=x+1x=y-1f(x+1)=x^2+2x+2f(y)=(y-1)^2+2(y-1)+2f(y)=y^2-2y+1+2y-2+2f(y)=y^2+1f(x)=x^2+1 f(y)=y^2-2y+1+2y-2+2怎样的来?
f(y)=(y-1)^2+2(y-1)+2
=y^2-2y+1+2y-2+2
=y^2+1