f(x)=2^sin(2x-π/4) 这个函数是否为周期函数?为什么?

f(x)=（1+cotx)sin^2x-2sin(x+π/4)sin(x-π/4)还有一题, 已知函数f(x)=(1+1 anx)sin^2x+m sin(x+π/4)sin(x-π/4) f(x)=sin(x+π/4)图像怎样变成F(x)=cos(2x) 函数f(x)=2sin(x+π/4)sin(x-π/4)+sin2x的值域 求f【x】=2sin[x+π/4]sin[x-π/4]+sin2x的最大值 证明∫( 0,π／2 ) (f sin x/(f sin x+f cos x) dx=π /4 若f(x)=sin(π/4)x,求f(1)+f(2)+.+f(2010) 求导f(x) = 4x^3 + sin(x^2) 已知f(x)=cos^2x/1+sin^2x求f'(π/4)求导 设f(x)=sin(x+4/π),则f(2x)= 傅里叶级数作图f（x）=2sin[x] - sin[2x] + 2/3sin[3x] - 1/2sin[4x]我用mathematica输入程序Plot[{2sin[x],-2sin[x],2sin[x] - sin[2x],-2sin[x] + sin[2x],2sin[x] - sin[2x] + 2/3sin[3x],-2sin[x] + sin[2x] - 2/3sin[3x],2sin[x] - sin[2x] + 2/3si f(x)=cos(2x-x/3)+2sin(x-π/4)sin(x+π/4)sin(x+π/4)化简. f(x)=2sin^2(π/4+x)+根号3(sin^2x+cos^2x)f(x)=2sin^2(π/4+x)+根号3(sin^2x-cos^2x) 符号打错了 f(x)=(6sin^4x-7sin^2x+2)/(sin^2x-cos^2x) 已知函数f(x)=4sinx-2/1+sin²x 证明f(x+2π)=f(x) 已知函数f(x)=2^(2-x),x>=2;f(x)=sinπx/4,-2 f(sin^2x)=x/sinx 求f(x) f(x)=2sin(π/4 x+π/4) 计算f(1)+f(2)+f(3)+...f(2011)