数列{an}满足an+1=an-3(n>=1)且a1=7,则a3的值是

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/13 03:35:18
数列{an}满足an+1=an-3(n>=1)且a1=7,则a3的值是
x){6uӎN{w _lۜmhk~OG=OvLI45y13 {XoTO v6pEm9@Dm@< 6/.H̳Zg$jm[&Bul8 hOsO5@n L%.Cm c]Cؚkiik"D

数列{an}满足an+1=an-3(n>=1)且a1=7,则a3的值是
数列{an}满足an+1=an-3(n>=1)且a1=7,则a3的值是

数列{an}满足an+1=an-3(n>=1)且a1=7,则a3的值是
a2=a1-3=7-3=4
a3=a2-3=4-3=1

a(n+1)=an-3
a(n+1)-an=-3
∴数列是等差数列,公差d=-3
a3=a1+(3-1)d
=7+2*(-3)
=1