sin(a-b)=5/13,sin(a+b)= -5/13且a-b∈(π/2,π),a+b∈(3π/2,2π),求cos2b的值

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 16:56:38
sin(a-b)=5/13,sin(a+b)= -5/13且a-b∈(π/2,π),a+b∈(3π/2,2π),求cos2b的值
x)+HMҴ574<]Ɏ)@Gto79~OPD,h})9( {lig~ 3HGk 4PDf190\e >ٽiR@۞n~ڿ^F 15%z

sin(a-b)=5/13,sin(a+b)= -5/13且a-b∈(π/2,π),a+b∈(3π/2,2π),求cos2b的值
sin(a-b)=5/13,sin(a+b)= -5/13且a-b∈(π/2,π),a+b∈(3π/2,2π),求cos2b的值

sin(a-b)=5/13,sin(a+b)= -5/13且a-b∈(π/2,π),a+b∈(3π/2,2π),求cos2b的值
cos2b=cos[(a+b)-(a-b)]=cos(a+b)cos(a-b)+sin(a+b)sin(a-b)
cos(a-b)=-12/13,cos(a+b)=12/13代入求值即可.