a1=2/3 an=-3/2 n=14 求sn 等差数列
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a1=2/3 an=-3/2 n=14 求sn 等差数列
a1=2/3 an=-3/2 n=14 求sn 等差数列
a1=2/3 an=-3/2 n=14 求sn 等差数列
等差数列求和公式:
sn=(a1+an)n/2
=(2/3-3/2)*14/2
=-35/6
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S14=14(a1+a14)/2=7(a1+a14)=7(2/3-3/2)= - 35/6
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