log√3^9+log9^27+(1/4)log4^1/16

log√3^9+log9^27+(1/4)log4^1/16 log√3^9+log9^27+(1/4)log4^1/16 log9(x-5)+log9(x=+3)=1 9是那个log的底 如题{log(2√2) - 3log√3 - 3} / {log9 - log4 + 4} 求值:-log2log2√√√2 ,log4 (8)-log1/9 (3)-log√2 (4) ; (log4(3))*（log9(25))*(log5(8)) log4^27×log(8)25×log9^5 log4^27×log(8)25×log9^5 计算一下对数题log√3 9+log9 27+（¼）^log4 1/16 这道题用统一成常用对数的方法去解应该怎么算啊?还有没有其他方法啊? log9 3+log9 27=怎么求~ 计算:(1/4)^log4^1/3-lg25-lg4-log9^27 计算：（log4 9+log8 3)(log3 2+log9 2)-log1/3 4√81log后面的第一个数都是小数字，最后边是81的4次方根 (log3 4+log3 8)(log2 3+log2 9)+(log3 根号2)(log9 7)/(log1/3 7)(log三次根号4 8) log4(3)*log9(2)+log2(4倍根号下64) log9(32)*log64(2log4(3)*log9(2)+log2(4倍根号下64) log9(32)*log64(27)+log9(2)*log4(根27) 1、log下标3 2(log下标4 3+log下标8 3)2、log下标1/3 √27+log下标27 1/3 log以3为底数2的对数和log9为底数4的对数一样么,能写个过程么 log(2)5×log(5)81×log(3)4＋In√e.还有(log(2)3＋log(4)9)(log(3)4＋1／2log(3)2) 对数不同底数相乘如何运算,(log以4为底3+log以8为底3)*(log3为底2+log9为底2)求教~ -5log9 4+log3 32/9-5^log5 3-(1/64)^-2/3