数列an满足an+1=2an (0≤an<1/2) 2an-1 (1/2≤an<1) 若a1=6/7 则a2010的值为
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数列an满足an+1=2an (0≤an<1/2) 2an-1 (1/2≤an<1) 若a1=6/7 则a2010的值为
数列an满足an+1=2an (0≤an<1/2) 2an-1 (1/2≤an<1) 若a1=6/7 则a2010的值为
数列an满足an+1=2an (0≤an<1/2) 2an-1 (1/2≤an<1) 若a1=6/7 则a2010的值为
a1=6/7>1/2
a2=2a1-1=5/7>1/2
a3=2a2-1=3/7<1/2
a4=2a3=6/7
…………
规律:从第一项开始,数列按6/7、5/7、3/7循环,每3个循环一次.
2010÷3=670,正好循环670次,a2010=3/7
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