若a+3b=0,则[1-b/a+2b]÷a+2ab+b/a-4b=?
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/16 10:51:48
x){ѽ4Q8@ihC$DmہTb6kdkoTOZ;Lր(ր ЌUH5NRx7~[$]2V #I3*
$lPӑ@j| h
dEtMqF6yv TiK
若a+3b=0,则[1-b/a+2b]÷a+2ab+b/a-4b=?
若a+3b=0,则[1-b/a+2b]÷a+2ab+b/a-4b=?
若a+3b=0,则[1-b/a+2b]÷a+2ab+b/a-4b=?
若a+3b=0,则[1-(b/a+2b)]÷[(a+2ab+b)/(a-4b)]=?a+3b=0 a=-3b 原式=[(a+2b-b)/(a+2b)]÷(a+b)^2/(a+2b)(a-2b) =(a+b)/(a+2b)×(a+2b)(a-2b)/(a+b)^2 =(a-2b)/(a+b) =(-3b-2b)/(-3b+b) =-5b/(-2b) =5/2