证明|arctanx2-arctanx1|

证明不等式arctanx2-arctanx1 证明|arctanx2-arctanx1| 在这个题的证明:arctanX2-arctanX1 1.设f（x）为偶函数,且f'（0）存在,证明f'（0）＝02.证明不等式｜arctanX2－arctanX1｜≤｜X2－X1｜ 反三角函数由于arcTanx在(-π/2,π/2)上是增函数,应该可以得到arcTanx1+arcTanx2=arcTan(x1+x2)吧?那arcTanx1+arcTanx2=什么? 设X1、X2是方程X^2-Xsin(π/5)+cos(4π/5)=0的两根,求arctanx1+arctanx2的值 设arctanx1=a,arctanx2=b设X1、X2是方程X^2-Xsin(π/5)+cos(4π/5)=0的两根,求arctanx1+arctanx2的值 设arctanx1=a,arctanx2=b,则tana=x1,tanb=x2又因为x1+x2=si 已知方程x平方加3根号3x加4=0的两个实数为x1,x2,则arctanx1加arctanx2=?急 已知x1,x2是方程x^2+3√3x+4=0两根,记α=arctanx1,β=arctanx2,求α+β的值 设方程x^2+3√3x+4=0的两个实数根为x1,x2,求arctanx1+arctanx2的值 设X1,X2是方程x²-xsin(π/5)-cos（π/5）=0的两根,则arctanx1+arctanx2的值是? 设x1,x2是方程x²-xsinπ/5+cos4π/5=0的两根,求arctanx1+arctanx2的值RT 设X1,X2是方程x2-xsin(π/5)+cos(π/5)=0的两根,则arctanx1+arctanx2的值是? 设方程x²+3[sqrt(3)]x+4=0的实数根为x1,x2,α=arctanx1,β=arctanx2,求α+β 设X1、X2是方程X^2-Xsin(π/5)+cos(4π/5)=0的两根,求arctanx1+arctx2 设arctanx1=a,arctanx2=b,则tana设X1、X2是方程X^2-Xsin(π/5)+cos(4π/5)=0的两根,求arctanx1+arctx2设arctanx1=a,arctanx2=b,则tana=x1,tanb=x2又因为x1+x2=sin(π/5),x 已知x1,x2是方程x²+3√3x+4=0两根,记a=arctanx1,b=arctanx2,求a+b的值RT 设X1、X2是方程X^2-Xsin(π/5)+cos(4π/5)=0的两根,求arctanx1+arctanx2的值设arctanx1=a,arctanx2=b,则tana=x1，tanb=x2又因为x1+x2=sin(π/5)，x1*x2=cos(4π/5)所以tan(a+b)=(tana+tanb)/(1-tanatanb)=(x1+x2)/(1-x1x2)=sin(π/5)/[1-cos(4π/5) 设方程x^2+3根号3x+4=0的两实根为x1 x2 a=arctanx1b=arctanx2设方程x^2+3(根号3)x+4=0的两实根为x1 x2 a=(arctanx1)*b=arctanx2求a+b 已找方程x^2+mx+n=0有两个实根x1,x2,a=arctanx1,β=arctanx2（1）当m=3根号3,n=4时,求a+β的值.（2）m=-sinΘ,n=cosΘ,(0