作业帮log2[log1/2(log2x)]=log3[log1/3(log3y)]=0 比较XY的大小急,
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log2[log1/2(log2x)]=log3[log1/3(log3y)]=0 比较XY的大小急,
log2[log1/2(log2x)]=log3[log1/3(log3y)]=0 比较XY的大小
急,
log2[log1/2(log2x)]=log3[log1/3(log3y)]=0 比较XY的大小急,
log1/2(log2x)=1---> log2x=1/2--> x=2^(1/2)
log1/3(log3y)=1--->log3y=1/3--> y=3^(1/3)
x^6=8
log2[log1/2(log2x)]=0
log1/2(log2x)=1
log2x=1/2
x=2^1/2
log3[log1/3(log3y)]=0
log1/3(log3y)=1
log3y=1/3
y=3^1/3
3^1/3>2^1/2
y>x