x(x-1)(x+3)-x(x-20)^2+7x+1,其中2=1/2
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x(x-1)(x+3)-x(x-20)^2+7x+1,其中2=1/2
x(x-1)(x+3)-x(x-20)^2+7x+1,其中2=1/2
x(x-1)(x+3)-x(x-20)^2+7x+1,其中2=1/2
是不是x=1/2呀?x(x-1)(x+3)-x(x-20)^2+7x+1=(1/2)(-1/2)(7/2)-(1/2)[(-39/2)^2]+7(1/2)+1=-7/8-1521/8+36/8=-1492/8=-373/2
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x/x+(1-x)/x-1/x
因式分解(x+1)(x-2)(x-3)(x-6)+20
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