作业帮计算,【1】[x(x^2-2x+3)-3x]÷1/2x^2 【2】[(2xy-3)(【1】[x(x^2-2x+3)-3x]÷1/2x^2【2】[(2xy-3)(2xy+3)+(xy+3^2]÷xy
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/02 21:37:07
![计算,【1】[x(x^2-2x+3)-3x]÷1/2x^2 【2】[(2xy-3)(【1】[x(x^2-2x+3)-3x]÷1/2x^2【2】[(2xy-3)(2xy+3)+(xy+3^2]÷xy](/uploads/image/z/1988148-12-8.jpg?t=%E8%AE%A1%E7%AE%97%2C%E3%80%901%E3%80%91%5Bx%28x%5E2-2x%2B3%29-3x%5D%C3%B71%2F2x%5E2+%E3%80%902%E3%80%91%5B%282xy-3%29%28%E3%80%901%E3%80%91%5Bx%28x%5E2-2x%2B3%29-3x%5D%C3%B71%2F2x%5E2%E3%80%902%E3%80%91%5B%282xy-3%29%282xy%2B3%29%2B%28xy%2B3%5E2%5D%C3%B7xy)
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计算,【1】[x(x^2-2x+3)-3x]÷1/2x^2 【2】[(2xy-3)(【1】[x(x^2-2x+3)-3x]÷1/2x^2【2】[(2xy-3)(2xy+3)+(xy+3^2]÷xy
计算,【1】[x(x^2-2x+3)-3x]÷1/2x^2 【2】[(2xy-3)(
【1】[x(x^2-2x+3)-3x]÷1/2x^2
【2】[(2xy-3)(2xy+3)+(xy+3^2]÷xy
计算,【1】[x(x^2-2x+3)-3x]÷1/2x^2 【2】[(2xy-3)(【1】[x(x^2-2x+3)-3x]÷1/2x^2【2】[(2xy-3)(2xy+3)+(xy+3^2]÷xy
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