x-5y-2z=6 3x+2y-6=1 5x+y-10=1 送迅雷vipx-5y-2z=6 3x+2y-6z=1 5x+y-10z=1LOLhh5828 99195528

来源：学生作业帮助网 编辑：作业帮 时间：2024/11/15 19:24:06
x-5y-2z=6 3x+2y-6=1 5x+y-10=1 送迅雷vipx-5y-2z=6 3x+2y-6z=1 5x+y-10z=1LOLhh5828 99195528
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x-5y-2z=6 3x+2y-6=1 5x+y-10=1 送迅雷vipx-5y-2z=6 3x+2y-6z=1 5x+y-10z=1LOLhh5828 99195528
x-5y-2z=6 3x+2y-6=1 5x+y-10=1 送迅雷vip
x-5y-2z=6 3x+2y-6z=1 5x+y-10z=1
LOL
hh5828 99195528

x-5y-2z=6 3x+2y-6=1 5x+y-10=1 送迅雷vipx-5y-2z=6 3x+2y-6z=1 5x+y-10z=1LOLhh5828 99195528
【参考答案】
x-5y-2z=6 ①
3x+2y-6z=1 ②
5x+y-10z=1 ③
①×3-②得
y=-1
分别把y=-1带入①、③得
x-2z=1 ④
x-5z=1 ⑤
④-⑤得 z=0
把z=0带入④得 x=1
∴ 原方程组的解是x=1,y=-1,z=0

先算后两项的 组成二元一次方程组 解得x=15/7 y=2/7 带入前面的第一式中可得z=-37/14

5x+y=11
y=11-5x
3x+2（11-5x）-6=1
22-7x-6=1
x=15/7
y=11-75/7=2/7
15/7-10/7-2z=6
5/7-6=2z
z=-37/14
题都给错了，楼上还能答对，这不能不让人怀疑是刷分

∵3x+2y-6=1 5x+y-10=1 所以3x-2y=7 5x+y=11 把这两个组成方程组解得：x=7分之15 y=7分之2 由此可求出z=负的14分之37

由1式可知x=6+2z+5y
由2式可知6z+17y=-11,即z=(-11-17)/6
将推得的以上两式子代入式子三可知y=2/7
将y=2/7代入推得的以上两式子可得z=-33/7,x=-2

3元一次方程啊…
X＝－7
Y＝18
Z＝－103╱2

看不清楚追问，楼主采纳！！

x+y+z=6 x+2y+3z=14 y+1=z x-y+z=-1 5x+2y-z=6 4x-3y+2z=-5 x+y+z=1 4x+5y-z=6 x+2y-z=3 1.{x:y:z=3:4:5 2x+3y-5z=-142.{x-y-z=-1 3x+5y+7z=11 4x-y+2z=-13.{x+y=1 x+z=0 2x+y+2z=44.{x-y+z=-3 2x-y-z=-2 -3x+y+z=-15.{x-y+z=-3 3x+y-4z=6 2x+y-z=36.{x-2y+5z=16 2x+y-5z=7 2x-y+z=38 已知x:：y：z=3：4：5,(1)求x+y分之z的值；（2）若x+y+z=6,求x,y,z. 若X:Y:Z=5:6:7那么(Y-X):(Y+Z)和(X+2Y+3Z):(3X+2Y+Z) ..1.x+y+z=26,2.4y+3z=7,y-z=1,3x+2z=17,x+2y-z=18 9x-7y=173.x-7y+3z=17 4.2x+4y+3z=95x-6y-z=24 3x-2y+5z=113x+7y-2z=1 5x-6y+7z=131.x+y+z=26,y-z=1x+2y-z=18 2.4y+3z=7,3x+2z=11,9x-7y=17 3.x-7y+3z=17 5x-6y-z=24 3x+7y-2z=14.2x+4y+3z=93x-2y+5z=11 5x-6y+7z=13 解三元一次方程组：(1)x+2y+3z=11x-y+4z=10x+3y+2z=2(2)x:y=3:5y:z=5:6x+y+2z=40(3)x+y-z=2y+z-x=4z+x-y=6谢谢! (1)2X+4Y+3Z=93X-2Y+5Z=115X-6Y+7Z=13(2)X:Y=3:2Y:Z=5:4X+Y+Z=66(3)3X-Y+Z=32X+Y-3Z=11X+Y+Z=13以上3个题目为三元一次方程~ 已知3x=4Y,5Y=6Z,求 (1)x:y:z;（2）x+y/y+z.请说明道理， 已知3x=4Y,5Y=6Z,求 (1)x:y:z;(2)x+y/y+z 三元一次方程组求解!1) X+Y+Z= 1 X+Y+2Z=2 X+3Y+Z=3 2) X+Y+Z=1 X+Y+2Z=2 X+3Y+Z=...三元一次方程组求解!1) X+Y+Z= 1X+Y+2Z=2X+3Y+Z=32) X+Y+Z=1X+Y+2Z=2X+3Y+Z=43) X+Y+Z=1X+Y+2Z=2X+3Y+Z=24) X+Y+Z=5X+Y+2Z=6X+3Y+Z=75) X+Y+Z=5X+Y+2Z=6X+3Y+2Z=76) 解三元一次方程 {y=2x-1 {3x+y+5z=9 {x+2y=3z=6 {x+y+z=26 {x-y=1 {2x-y+z=18 {x-y+z=6,x+3y=-1,y+2z=3 (1)X+Y=15,Y+Z=-6,Z+X=7.(2)X+Y=-14,Y+Z=-7,Z+X=9.(3)X+Y=0,Y+Z=-1,Z+X=-1. 4X+3Y-2Z=-7,5X-6Y+Z=1,2X+Z=-2 4X+3Y-2Z=-7,5X-6Y+Z=1,2X+Z=-2 如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,