设m>1,在约束条件{y大于等于x；y小于等于mx；x+y小于等于1}的条件下,目标函数z=x+my的最小值小于2,求m的取值范围

设m>1,在约束条件{y大于等于x；y小于等于mx；x+y小于等于1}的条件下,目标函数z=x+my的最小值小于2,求m的取值范围
设m>1,在约束条件{y大于等于x；y小于等于mx；x+y小于等于1}的条件下,目标函数z=x+my的最小值小于2,求m的取值范围

设m>1,在约束条件{y大于等于x；y小于等于mx；x+y小于等于1}的条件下,目标函数z=x+my的最小值小于2,求m的取值范围
我来试试吧.
约束条件 y≥x
y≤mx
x+y≤1
m>1,作图做出约束条件 y=x（右）
y=mx（左）
y=1-x(左)
故约束条件范围是在第三象限,夹在y=x和y=mx中间的部分
目标函数z=x+my（m>1）
做出y=-1/mx的图像..在y轴上的截距设为d,需求d的最小值..
显然此时最小值不存在...

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约束区域是在第一象限的一个经过原点的三角形，z=x+my =>x=-my+z
z可以看成是直线x=-my+z在x轴上的截距
在约束区域内平移直线x=-my，不难看出在原点有最小截距，此时z=0<2，自然满足
所以只需满足初始条件m>1
这题你是不是抄错了？再看看吧