已知3^M=6,9^N=2,求2^2M-4N+1
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已知3^M=6,9^N=2,求2^2M-4N+1
已知3^M=6,9^N=2,求2^2M-4N+1
已知3^M=6,9^N=2,求2^2M-4N+1
9^n=2,3^(2n)=2,因为3^m=6,所以3^m/3^(2n)=3^(m-2n)=6/2=3
所以m-2n=1
2^(2m-4n+1)=2^[2(m-2n)+1]=2^[2+1]=2^3=8
还是
[2^(2m-4n)]+1=[2^2]+1=5
下次要用括号标明数字运算,在电脑上才会明白
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