x²-xy-3x=0,x²+y+1=0

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x²-xy-3x=0,x²+y+1=0
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x²-xy-3x=0,x²+y+1=0
x²-xy-3x=0,x²+y+1=0

x²-xy-3x=0,x²+y+1=0
由x²+y+1=0,得y=-x²-1,代入x²-xy-3x=0,得:
  x²-x(-x²-1)-3x=0
  x³+x²-2x=0
  x(x²+x-2)=0
  x(x+2)(x-1)=0 得出:x=0,1,-2
  x=0时:y=-x²-1=-1
  x=1时:y=-x²-1=-2
  x=-2时:y=-x²-1=-5