(sin^2b+cos^2b)^2-2sin^2bcos^2b=1-1/2sin^2b这里的1/2sin^22b是怎么得来的
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(sin^2b+cos^2b)^2-2sin^2bcos^2b=1-1/2sin^2b这里的1/2sin^22b是怎么得来的
(sin^2b+cos^2b)^2-2sin^2bcos^2b=1-1/2sin^2b这里的1/2sin^22b是怎么得来的
(sin^2b+cos^2b)^2-2sin^2bcos^2b=1-1/2sin^2b这里的1/2sin^22b是怎么得来的
sin^2b+cos^2b=1
二倍角公式
∵sin2b=2sinbcosb
∴sincosb=1/2sin2b
∴sin²bcos²b=1/4sin²2b
∴2sin²bcos²b=1/2*sin²2b
∴(sin^2b+cos^2b)^2-2sin^2bcos^2b=1-1/2sin^2b
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