(sin^2b+cos^2b)^2-2sin^2bcos^2b=1-1/2sin^2b这里的1/2sin^22b是怎么得来的

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 14:58:20
(sin^2b+cos^2b)^2-2sin^2bcos^2b=1-1/2sin^2b这里的1/2sin^22b是怎么得来的
x)(̋3JN/RqFF>T/{j%=YCߓOM6w)P&Hȭ(fŞybk= T T2dcTx B2BWS64LF8iaQLB0$ف Ö

(sin^2b+cos^2b)^2-2sin^2bcos^2b=1-1/2sin^2b这里的1/2sin^22b是怎么得来的
(sin^2b+cos^2b)^2-2sin^2bcos^2b=1-1/2sin^2b这里的1/2sin^22b是怎么得来的

(sin^2b+cos^2b)^2-2sin^2bcos^2b=1-1/2sin^2b这里的1/2sin^22b是怎么得来的
sin^2b+cos^2b=1
二倍角公式
∵sin2b=2sinbcosb
∴sincosb=1/2sin2b
∴sin²bcos²b=1/4sin²2b
∴2sin²bcos²b=1/2*sin²2b
∴(sin^2b+cos^2b)^2-2sin^2bcos^2b=1-1/2sin^2b