[(x-3y)²-(x+3y)²]÷(-2xy)
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[(x-3y)²-(x+3y)²]÷(-2xy)
[(x-3y)²-(x+3y)²]÷(-2xy)
[(x-3y)²-(x+3y)²]÷(-2xy)
[(x-3y)²-(x+3y)²]÷(-2xy)
=[(x-3y)+(x+3y)][(x-3y)-(x+3y)]÷(-2xy)
=2x×(-6y)÷(-2xy)
=6