X/(Y-Z)+Y/(Z-X)+Z/(X-Y)=0求证X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0通过上面求证下面^2是……的2次方X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0

来源：学生作业帮助网编辑：作业帮时间：2024/11/03 04:11:59

x��)��׈ԍ�Ԏ�׈ҍ�Ԏ�׈ЍԴ5x��F�t�L�Ugdk�a֋��Ovt��Ɏn ;��ٌ��Y-F��,|6m'�l��q;,�Y!^�HrQ��0�Յ*х*P��YgÓ�K��@�j��0 `TA�n$XL7 �.IX�L#Ră�"$�N�y>� ��nؙP7!�B�. v̱�"g8��)��H�Arц]چ5��X�E�� ̉x�� Q�d��ӆ=/z��~�|lʟuL|��ɞYH�\�\

X/(Y-Z)+Y/(Z-X)+Z/(X-Y)=0求证X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0通过上面求证下面^2是……的2次方X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0
X/(Y-Z)+Y/(Z-X)+Z/(X-Y)=0
求证
X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0
通过上面求证下面^2是……的2次方
X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0

X/(Y-Z)+Y/(Z-X)+Z/(X-Y)=0求证X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0通过上面求证下面^2是……的2次方X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2=0
X/(Y-Z)=-Y/(Z-X)-Z/(X-Y)
所以X/(Y-Z)^2
=-Y/(Z-X)(Y-Z)-Z/(X-Y)(Y-Z)
=[-Y(X-Y)-Z(Z-X)]/(X-Y)(Y-Z)(Z-X)
=(Y+Z-X)/(X-Y)(Z-X)
同理
Y/(Z-X)^2=-Z/(X-Y)(Z-X)-X/(Y-Z)(Z-X)
Z/(X-Y)^2=-X/(Y-Z)(X-Y)-Y/(Z-X)(X-Y)
所以
X/(Y-Z)^2+Y/(Z-X)^2+Z/(X-Y)^2
=(Y+Z-X)/(X-Y)(Z-X)-Z/(X-Y)(Z-X)-X/(Y-Z)(Z-X)-X/(Y-Z)(X-Y)-Y/(Z-X)(X-Y)
=-X/(X-Y)(Z-X)-X/(Y-Z)(Z-X)-X/(Y-Z)(X-Y)
=-X/(Z-X)[1/(X-Y)+1/(Y-Z)]-X/(Y-Z)(X-Y)
=X/(Y-Z)(X-Y)-X/(Y-Z)(X-Y)
=0

X、Y、Z的取值范围？

我不会

x-y/(z-x)(z-y) 一y-z/(x-y)(x-z) ＋z-x/(y-z)(y-x) x^-(y-z)^/(x+y)^-z^ 计算（x+y-z)(x-y-z) 计算：(x-y+z)(-x+y+z) (x+y-z)(x-y+z)= x y y ...y z x y ...y z z x ...y ........z z z ...x 求解行列式. x+y>z 0 用乘法公式计算(x+y)(x-y)+(-y-z)(-y+z)+(-x+z)(z+x) 计算：（X+y+z)(-x+y+z)(x-y+z)(x+y-z) （x+y-z）（x-y+z）-（x+y+z）（x-y-z）因式分解：（x+y-z)(x-y-z)+(y-x+z)(y-x-z) 因式分解测试题x(x+y-z)+y(x+y-z)+z(z-x-y) (x+y+z)(-x+y+z)(x-y+z)(x+y-z)等于什么? (x-y+z)² （x+y-z）*（x+y-z)-(x-y+z)*(x-y-z)等于多少计算(x+y+z)(-x+y+z)(x-y+z)(x+y-z) 如何化简(x+y+z)(x+y-z)(x-y+z)(-x+y+z) 方向 X Y Z