求sin25π/6+cos5π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-5π/6)×cos(-5π/3)的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/06 05:15:06
x){83|vr~1a]4k蚃5O*54)ˀd5jyڰ&H7l-H|6Xd]f.
((f$\6uA|$"go
@jG44]8"!:t<;P Wg
求sin25π/6+cos5π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-5π/6)×cos(-5π/3)的值
求sin25π/6+cos5π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-5π/6)×cos(-5π/3)的值
求sin25π/6+cos5π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-5π/6)×cos(-5π/3)的值
sin25π/6+cos5π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-5π/6)×cos(-5π/3)
=sin(4π+π/6)+cos(2π-π/3)+tan(-6π-π/4)+sin(-2π-π/3)*cos(-2π-π/6)-sin(-2π+π-π/6)*cos(-2π+π/3)
=sin(π/6)+cos(-π/3)+tan(-π/4)+sin(-π/3)*cos(-π/6)-sin(-π/6)*cos(π/3)
=1/2+1/2+(-1)+(-√3/2)*(√3/2)-(-1/2)*(1/2)
= - 1/2
求sin25π/6+cos5π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-5π/6)×cos(-5π/3)的值
sin25π/6等于?
计算cos5分之π+cos5分之2π+cos5分之3π+cos5分之4π
计算cos5分之π+cos5分之2π+cos5分之3π+cos5分之4π
计算不太明白...求值sin(-1320°)*cos1110°+cos(-1020°)sin750°+tan(-405°)求值sin25π/6+cos25π/3+tan25π/4+sin7π/3*cos13π/6-cos5π/3
sin25π/3 结果是多少.
求sin25π/6+cos25π/3+tan(-25π/4)的值?
sin25π/6+cos25π/3+tan(-25π/4)
计算sin25/6π+tan9/4π-cos19/3π
计算sin25/6π+tan9/4π-cos19/3π
sin25/6π+cos4/3π等于多少?
求cos5π/12sinπ/12
cos5分之π×cos5分之2π
sin(-4/3π)+cos5/6π=
sin5/3π= ,cos5/3π
cos5π/3为什么等于1/2?
COS5π/3=要步骤
cos5π等于=