设A={x|2x^2+ax+2=0},B={x|x^2+3x+2a=0},A∪B={0.5,-5,2},求A∩B

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设A={x|2x^2+ax+2=0},B={x|x^2+3x+2a=0},A∪B={0.5,-5,2},求A∩B
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设A={x|2x^2+ax+2=0},B={x|x^2+3x+2a=0},A∪B={0.5,-5,2},求A∩B
设A={x|2x^2+ax+2=0},B={x|x^2+3x+2a=0},A∪B={0.5,-5,2},求A∩B

设A={x|2x^2+ax+2=0},B={x|x^2+3x+2a=0},A∪B={0.5,-5,2},求A∩B
2x^2+ax+2=0的根x1,x2属于{0.5,-5,2},
因为：x1*x2=2/2=1
所以,x1,x2分别为0.5,2
A={0.5,2}
x^2+3x+2a=0根x1,x2属于{0.5,-5,2},
因为：x1+x2=-3
所以,x1,x2分别为-5,2
B={-5,2}
A∩B={2}

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