lim(x→∞)[(x^2-2x+1)/(x+1)直接化简即可：lim(x→∞)[(x^2-2x+1)/(x+1)]=lim(x→∞)[(x^2+x-3x-3+4)/(x+1)]=lim(x→∞)[x-3+4/(x+1)]我不知道下面这一步是怎么得来的:=lim(x→∞)[(x^2+x-3x-3+4)/(x+1)]=lim(x→∞)[x-3+4/(x+1)]x^

来源：学生作业帮助网编辑：作业帮时间：2024/11/15 05:41:35

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lim(x→∞)[(x^2-2x+1)/(x+1)直接化简即可：lim(x→∞)[(x^2-2x+1)/(x+1)]=lim(x→∞)[(x^2+x-3x-3+4)/(x+1)]=lim(x→∞)[x-3+4/(x+1)]我不知道下面这一步是怎么得来的:=lim(x→∞)[(x^2+x-3x-3+4)/(x+1)]=lim(x→∞)[x-3+4/(x+1)]x^
lim(x→∞)[(x^2-2x+1)/(x+1)直接化简即可：
lim(x→∞)[(x^2-2x+1)/(x+1)]
=lim(x→∞)[(x^2+x-3x-3+4)/(x+1)]
=lim(x→∞)[x-3+4/(x+1)]
我不知道下面这一步是怎么得来的:
=lim(x→∞)[(x^2+x-3x-3+4)/(x+1)]
=lim(x→∞)[x-3+4/(x+1)]
x^2-3x去哪里了呢?

lim(x→∞)[(x^2-2x+1)/(x+1)直接化简即可：lim(x→∞)[(x^2-2x+1)/(x+1)]=lim(x→∞)[(x^2+x-3x-3+4)/(x+1)]=lim(x→∞)[x-3+4/(x+1)]我不知道下面这一步是怎么得来的:=lim(x→∞)[(x^2+x-3x-3+4)/(x+1)]=lim(x→∞)[x-3+4/(x+1)]x^
lim（x→∞）[（x²＋x－3x－3+4）／（x+1）]
＝lim（x→∞）｛[（x²+x）-3（x+1）+4]／（x+1）｝
＝lim（x→∞）[（x²+x）／（x+1）－3（x+1）／（x+1）＋4／（x+1）]
=lim（x→∞）[x-3+4／（x+1）]

Lim [x^2/(x^2-1)]^x (x→∞) lim(1+x/x)2x (x→∞) lim(x)lim(x→∞) [(x-1)/(x+1)]^2x 为什么 lim(x->∞) {[(-2)/(x+1)]*2x} = -4 x/2-1lim(1-2/x)x→∞ lim(x→∞)(1-2/x)^2x lim(x→∞)(1-2/x) (x+1)次方 lim(x→∞)[1+(1/x)]^x/2 lim x→∞(2x+1)/(3x-4) lim x→∞ x-1/x^2 lim x→∞(1-2/x)^x= 求lim(√x^2+1)-x x→-∞ 求lim(x→0)x cos 1/x lim(x→∞)x^2/ (3x-1)的极限 lim xsin(2/x) x→∞ lim x→1 x-1/x^2-x lim(x→0)e^x-x-1/x^2 lim(x→∞)[(X^2+2x+5)/(3x^2-x+1) = lim(x→∞)(4x^3+2x-1)/(2x^3-3x+1) lim(x→∞)(2x^3-x^2-3)/(x^3-x+1)