若x∧2-y∧2=24,x+y=6,x+2y=?

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若x∧2-y∧2=24,x+y=6,x+2y=?
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若x∧2-y∧2=24,x+y=6,x+2y=?
若x∧2-y∧2=24,x+y=6,x+2y=?

若x∧2-y∧2=24,x+y=6,x+2y=?
x-y
=(x-y)(x+y)/(x+y)
=(x²-y²)/(x+y)
=24/6
=4
与x+y=6 联立
2x=10
x=5
y=6-x=6-5=1
x+2y=5+2x1=7
如果本题有什么不明白可以追问,

x²-y²=(x+y)(x-y)=24
x+y=6
所以x-y=4
相加
2x=10
x=5
y=6-x=1
所以x+2y=7

x∧2-y∧2=24
(x+y)(x-y)=24
x+y=6
x-y=4
x=5,y=1

x+2y=5+2=7

满意请采纳，O(∩_∩)O谢谢~

x+y=6
∴x-y=(x+y)(x-y)/(x+y)
=(x²-y²)/(x+y)
=24/6
=4
解得x=5, y=1
x+2y=5+2=7


x²－y²＝24, x＋y＝6
x²－y²＝（x－y）（x＋y）＝24
∴x－y＝4
x＋y＝6
解得： x＝5
y＝1
∴x＋2y＝5＋1×2＝7.

x²-y²=（x+y）（x-y）=6（x-y)=24
∴x-y=4
与x+y=6联立方程组，解得：
x=5，y=1
∴x+2y=5+2=7

7


x²－y²＝24, x＋y＝6
x²－y²＝（x－y）（x＋y）＝24
∴x－y＝4
x＋y＝6
解得：x＝5，y＝1
∴x＋2y＝5＋1×2＝7.
望采纳。

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