已知数列{an}满足a1=1/2,a(n+1)=an+1/(n2+n),求an用累加法
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已知数列{an}满足a1=1/2,a(n+1)=an+1/(n2+n),求an用累加法
已知数列{an}满足a1=1/2,a(n+1)=an+1/(n2+n),求an
用累加法
已知数列{an}满足a1=1/2,a(n+1)=an+1/(n2+n),求an用累加法
a(n+1)-an=1/n-1/(n+1)
所以
an-a(n-1)=1/(n-1)-1/n
...
a2-a1=1-1/2
上面式子相加
an-a1=1-1/n
an=3/2-1/n
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