(1+x)(x-1/x²+x-1-x/x的3次方-x）3x-6/x²-4÷(x+2/x²+4x+4) -2

计算x²-x/x²×x/1-x和x²-4y²/x²+2xy+y²÷x+2y/x²+xy (x²-4分之x²+x+1)²÷(x三次方-3x²+2x÷x三次方)²×(x÷x+2)² , (x² +x+1)/(x² +1)+(2x² +x+2)/(x² +x+1) =19/6化成(x² +x+1)/(x² +1)+(x² +1)/(x² +x+1)=13/6急嗷 化简~(x²+3x+9/x²-27)+(6x/9x-x²)-(x-1/6+2x)(x²+3x+9/x²-27)+(6x/9x-x²)-(x-1/6+2x)注意了!是三个分式!(x²+3x+9)/(x²-27)+(6x)/(9x-x²)-(x-1)/(6+2x) log2(x²+1) xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 x²+2x+2 / x+1=x²+4x+6 / x+2 -1 x²-1分之x²+x,化简x²-6x+9分之x²-9化简...T (x²+1)²-4x² 分解因式 3x/(x²-2x),(2x+1)/(4-x²),3/(2x²+4x)通分~ 两个初升高衔接教材的数学题.①(x²+x+1)(x²+x+2)-12=(x²+x+1)(x²+x+1+1)-12=(x²+x+1)²+(x²+x+1)-12=(x²+x-3)(x²+x+5)[十字相乘法]②(x²+x)²-8(x²+x)+12=(x²+x-2)(x²+x-6)[ x⁴-a²x²-b²x²+a²b²x²(x+1)-y(xy+x) 已知2x²+2x-3=0 求代数式x(x²-x-1)+2(x²+1)-1/3x(3x²+6x) x²-1/x²-2x+1÷x+1/x-1 X 1-x/1+x 1(x²-9)/(x²+2x²+x)*(3x³+9x²)/(x³-3x),其中x=-1/3 1.(8xy-x²+y²)-(x²-y²+8xy)2.(2x²-1/2+3x)-4(x-x²+1/2)3.3x²-[7x-(4x-3)-2x²] 设函数f(x)={a/x+b/(x²-x) x>1{x x 因式分解：(2x²-3x+1)²-22x²+33x-1