已知数列{an}中,a1=1/2,a(n+1)=an+1/(4n^2-1),则an=

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已知数列{an}中,a1=1/2,a(n+1)=an+1/(4n^2-1),则an=
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已知数列{an}中,a1=1/2,a(n+1)=an+1/(4n^2-1),则an=
已知数列{an}中,a1=1/2,a(n+1)=an+1/(4n^2-1),则an=

已知数列{an}中,a1=1/2,a(n+1)=an+1/(4n^2-1),则an=

a(n+1)
=an+1/(4n^2-1)
=an+1/(2n+1)(2n-1)
=an+1/2*[1/(2n-1)-1/(2n+1)],

an=a(n-1)+1/2*[1/(2n-3)-1/(2n-1)],
a(n-1)=a(n-2)+1/2*[1/(2n-5)-1/(2n-3)],
.
a3=a2+1/2*(1/3-1/5)
a2=a1+1/2*(1/1-1/3),
两边相加,消去中间项得
an=a1+1/2*[1-1/(2n-1)]
=1-1/[2(2n-1)].