若(x^2+y^2)(x^2+y^2-1)-12=0,且x,y为实数,则x^2+y^2=?
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/16 00:03:08
x){ѽT"H2H5545ycJNl3Jlm)Э_`gC0^ WQӪ 5/.H̳ *ZY
若(x^2+y^2)(x^2+y^2-1)-12=0,且x,y为实数,则x^2+y^2=?
若(x^2+y^2)(x^2+y^2-1)-12=0,且x,y为实数,则x^2+y^2=?
若(x^2+y^2)(x^2+y^2-1)-12=0,且x,y为实数,则x^2+y^2=?
x^2+y^2=t
t(t-1)-12=0
t=4
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
[(-x-y)(-x+y)-(x+y)^2-x(y-y^2)}÷1/2y
若x*x+y*y=x+y-1/2,求x,y的值如题
化简y(x+y)+(x+y)(x-y)-x^2
(x+y)(x-y)-(x-y)^2如题 (x+y)(x-y)-(x-y)^2
【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y)
因式分解x(x+y)(x-y)-x(x+y)^2
1、y-x/x²-y²2、(x-y)(y-z)(z-x)/(z-y)(y-x)(x-z)
(x-y)(2x-y-1)
(x/x+y-x/y-x-2xy/x.x-y.y)/(1/x-1/y) 分式化简
[(x-y)^2-(x+2y)(x-2y)]/y
计算:y-x分之x+y+x-y分之y-y-x分之2x-y
x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x²
2y(x+二分之一y)-[(x+y)(x-y)+2y(y+x)],其中|x-1|=2
(x-y)(x+y)-(x+y)^2+2y(y-x),其中x=1,y=3.
x^2(x-y)+(y-x)
x(x-y)2-(y-x)3