f(x+2)=x方-x+1,则f(x)等于

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f(x+2)=x方-x+1,则f(x)等于
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f(x+2)=x方-x+1,则f(x)等于
f(x+2)=x方-x+1,则f(x)等于

f(x+2)=x方-x+1,则f(x)等于
令t=x+2则x=t-2f(t)=(t-2)²-(t-2)+1=t²-4t+4-t+2+1=t²-5t+7即f(x)=x²-5x+7

令t=x+2
则x=t-2
f(t)=(t-2)²-(t-2)+1
=t²-4t+4-t+2+1
=t²-5t+7
即f(x)=x²-5x+7
望采纳,谢谢

f(x+2)=x²-x+1=(x+2)²-4x-4-x+1=(x+2)²-5x-10+7=(x+2)²-5(x+2)+7
所以f(x)=x²-5x+7

把x换成(x-2)得:
f(x)=(x-2)^2-(x-2)+1
=x^2-5x+7

同学,请问是平方吗?