7a-8b=5,求(3a-4b)(7a-8b)-(11a-12b)(8b-7a)

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7a-8b=5,求(3a-4b)(7a-8b)-(11a-12b)(8b-7a)
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7a-8b=5,求(3a-4b)(7a-8b)-(11a-12b)(8b-7a)
7a-8b=5,求(3a-4b)(7a-8b)-(11a-12b)(8b-7a)

7a-8b=5,求(3a-4b)(7a-8b)-(11a-12b)(8b-7a)
(3a-4b)(7a-8b)-(11a-12b)(8b-7a)=(7a-8b)(3a-4b+11a-12b)
=5(14a-16b)=5*10=50

50

原式=((3a-4b)+(11a-12b))(7a-8b)=(14a-16b)(7a-8b)=2(7a-8b)^2
OK?
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