1+(dy/dx)^2=y^2怎么解求y
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1+(dy/dx)^2=y^2怎么解求y
1+(dy/dx)^2=y^2怎么解
求y
1+(dy/dx)^2=y^2怎么解求y
(dy/dx)=sqrt(y^2-1) which implies:dy/sqrt(y^2-1)=dx integrate both sides:integrate (1/sqrt(y^2-1))dy = x which leads to:ln|y+sqrt(y^2-1)|=x Please pay attention to the +/- after each steps.I didnt consider this issue here.
1+(dy/dx)^2=y^2怎么解求y
隐微分法求导数完全看不懂implicit differentiation(隐微分求导数).例子:y^2+y=3x^5-7x我明白下一步怎么变成2y(dy/dx)+1(dy/dx)=15x^4(dx/dx)-7(dx/dx)为什么它在两边求了导数之后,还要分别乘上dy/dx和dx/dx啊?
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反函数的二阶导数疑问设dy/dx=y',则dx/dy=1/y',应视为y的函数则d2x/dy2=d(dx/dy)/dy(定义)=d(1/(dy/dx)) / dy=d(1/(dy/dx))/dx * dx/dy(复合函数求导,x是中间变量)=-y''/(y')^2 * (1/y')=-y''/(y')^3d(1/(dy/dx))/dx * dx/dy
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