(x-2)/(x+2)+16/(4-x^2)=(x+2)/(x-2)
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/06 03:34:49
xSN@~mR¡sII@$*h"T>KgۅTpwN37_뮖I
DA* R4
1A\=M$Ѧaa0^eyâ%;λ182mkX?Ndu36E="[3GpecV5"sr|Ƌ)(Z
BH!$"va_;-6fcx}nڝK9w= #RbKn'a7>B8ZUnfI.,&;fREXC6pQ7=k(tG}2cU
(x-2)/(x+2)+16/(4-x^2)=(x+2)/(x-2)
(x-2)/(x+2)+16/(4-x^2)=(x+2)/(x-2)
(x-2)/(x+2)+16/(4-x^2)=(x+2)/(x-2)
方程两边同时乘以4-x^2得,-(x-2)^2+16=-(x+2)^2,整理得
x^2=8,x=±2倍根号2,经检验,不是增根.
X= -2
16/(4-x^2)=0 得16/(2-x)(2+x) =0 (2-x)(2+x) =0 得x=2或-2
(x-2)/(x+2)-16/[(x+2)(x-2)]=(x+2)/(x-2)
方程的左右两边同乘以(x+2)(X-2)
x^2-4x+4-16=x^2+4x+4
-8x=16
...
全部展开
(x-2)/(x+2)-16/[(x+2)(x-2)]=(x+2)/(x-2)
方程的左右两边同乘以(x+2)(X-2)
x^2-4x+4-16=x^2+4x+4
-8x=16
x=-2
检验:
把x=-2分别带入原方程的左右两边
因为分母不能为0
所以原方程无实数根
收起
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
(x/x-2-x/x+2)/4x/x-2
1/(1-x)+1/(1+x)+2/(1+x*x)+4/(1+x*x*x*x)+8/(1-x*x*x*x*x*x*x*x)怎么做
(x-2)(x+2)(x^4+4x^2+16)
(x-2)(x+2)(x^2+4)(x^4+16)
(x-2)(x^2+4)(x^4+16)(x+2)
(x^2 + 4x)(x^2 + 4x+8)+16
(x^2-4x)(x^2-4x+8)+16
x^2-8x+16分之x^2-4x
(x^2-4x)/x^2-8x+16
16x^4-4x^2+x)/x=?
(16x^4+4x^2+x)/x=?
因式分解:(X+2)(X+4)(X+6)(X+8)+16
(x+2)(x-2)+16 (x-1)(x-2)+3x(x+3)-4(x+2)(x-3)(x+2)(x-2)+16 (x-1)(x-2)+3x(x+3)-4(x+2)(x-3)
计算(x+/1x)(x^2+1/x^2)(x^4+1/x^4)(x^8+1/x^8)(x^16+1/x^16)(x^2-1)
(x+1/x)(x^2+1/x^2)(x^4+1/x^4)(x^8+1/x^8)(x^16+1/x^16)(x^2-1)
(x+x^-1)(x^2+x^-2)(x^4+x^-4)(x^8+x^-8)(x^16+x^-16)(x^2-1)=?
(x^2-8x+16)/(4-x^2)/(16-x^2)/(4+4x+x^2)