计算:log3 4·log4 5·log5 6…log80 81=
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计算:log3 4·log4 5·log5 6…log80 81=
计算:log3 4·log4 5·log5 6…log80 81=
计算:log3 4·log4 5·log5 6…log80 81=
运用换底公式得:
原式=lg4/lg3 *lg5/lg4 *lg6/lg5 *...*lg81/lg80
=lg81/lg3
=4lg3/lg3
=4
log3 4·log4 5·log5 6…log80 81
= lg4/lg3 × lg5/lg4 × lg6/lg5 ×… × lg81/lg80
= lg81/lg3
= 4
数学题计算log4 8-log1/9 3+log根号2 1/4计算log4 8-log1/9 3+log根号2 1/4计算【3^(log3 根号5)】+【根号3^(log3 1/5)】
计算:log3 4·log4 5·log5 6…log80 81=
(log2 5+log4 125)log3 2/ log根号3 5
log函数大小比较log3 2与log3 4 log3 12与log4 12 log0.5 2与log0.5 3 log0.5 2与log0.7 2
1/(2log3 4)=1/2·log4
log3(4)·log4(8)·log8(m)=log4(16)则m=
log2 3 · log3 4 ·log4 5 ·log5 2 前面的是底数
log2(3)*log3(4)*log4(5)*.log(k+1)(k+2)=log2(k+2) 怎么证
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log2(32)-log2(3÷4)+log2log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2【log2(32)-log2(3÷4)+log2(6)】=?lgx+lg(x+15)=2 ..X
log 2 3 * log3 4 * log4 5 *log5 2 化简log以2为底3的对数 .运用换底公式化简
log7(4)·log4(7)求值①log5(3)·log3(7)·log7(5)②log7(4)·log4(7)
利用对数的换底公式,计算.log2 5(不是25,以下同) ×log 5 4 =2?log2 3×log3 4×log4 5×log5 6×log6 7×log7 8=3?
利用换底公式计算下面题目?log2 5 x log5 4 log2 3 x log3 4 x log4 5 x log5 6 x log6 7 x log7 8 (log后面数字为底数小一点)
(log2(5)+log4(125))×log3(2)/log根号3(5)
(log2^5+log4^125)(log3^2)/(log(根号3)^5 要具体的过程,
(log2(5)+log4(125))(log3(2)/log√3(5))怎么解?
[log3(4)+log根下3(2)][log2(9)+log4(根3)]
log3 4×log4 8×log8 a=log根号3 9,则a=