(log3^2)(log2^3)=

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(log3^2)(log2^3)=
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(log3^2)(log2^3)=
(log3^2)(log2^3)=

(log3^2)(log2^3)=
底数是多少啊?

1

2>1,所以log2*x是增函数所以log2*3>log2*2=1 同理,log3*x是增函数 log3*1<log3*2<log3*3 0<log3*2<1 所以p>q>0 log3*2<1 所以log