作业帮cos2x/sin{x-π/4}=-根号2/2求cosx+sinx的值
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cos2x/sin{x-π/4}=-根号2/2求cosx+sinx的值
cos2x/sin{x-π/4}=-根号2/2求cosx+sinx的值
cos2x/sin{x-π/4}=-根号2/2求cosx+sinx的值
cos2x/sin{x-π/4}=(cos²x-sin²x)/[ 根号2/2(sinx-cosx)]
=-根号2 (cosx+sinx)
由已知得,-根号2 (cosx+sinx) =-根号2/2,
所以cosx+sinx=1/2.
若(cos2x)/[sin(x-π/4)]=（-根号2）/2,则cosx+sinx=?
若cos2x/sin(x-π/4）=-根号2/2,sin2x=?
cos2x/sin{x-π/4}=-根号2/2求cosx+sinx的值
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