数列1/2X5,1/5X8,1/8X11,、、、1/[(3N-1)X(3N+2)]的前N项和是
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数列1/2X5,1/5X8,1/8X11,、、、1/[(3N-1)X(3N+2)]的前N项和是
数列1/2X5,1/5X8,1/8X11,、、、1/[(3N-1)X(3N+2)]的前N项和是
数列1/2X5,1/5X8,1/8X11,、、、1/[(3N-1)X(3N+2)]的前N项和是
1/2X5+1/5X8+1/8X11+...+1/[(3N-1)X(3N+2)]
=1/3(1/2-1/5+1/5-1/8+...+1/(3n-1)-1/(3n+2))
=1/3*(1/2-1/(3n+2))
=n/[2(3n+2)]
1/[(3N-1)X(3N+2)]=1/3(1/(3N-1)-1/(3N+2)]
Sn=1/3[1/2-1/5+1/5-1/8+1/8-1/11+……+1/(3N-1)-1/(3N+2)]
=1/3[1/2-1/(3N+2)]
=N/2(3N+2)
已经有人回答了。
1/2x5+1/5x8+1/8x11+.+1/2006x2009+2009x2013用裂项法计算
裂项法1/2X5+1/5x8+1/8x11.1/2009x2012=?
1/2x5 +1/5x8 +1/8x11+……+1/2009x2012=?
数列1/2X5,1/5X8,1/8X11,、、、1/[(3N-1)X(3N+2)]的前N项和是
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